4x^2+12x-73=0

Solution for 4x^2+12x-73=0 equation:

4x^2+12x-73=0

a = 4; b = 12; c = -73;
Δ = b2-4ac
Δ = 122-4·4·(-73)
Δ = 1312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1312}=\sqrt{16*82}=\sqrt{16}*\sqrt{82}=4\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{82}}{2*4}=\frac{-12-4\sqrt{82}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{82}}{2*4}=\frac{-12+4\sqrt{82}}{8}
$